[最も欲しかった] tan^2x-sec^2x 2=cosec^2x-cot^2x 162922-(sec^2x+tan^2x)(cosec^2x+cot^2x)=1+2 sec^2x cosec^2x
Abhishek K LH S = sec2x csc2x = 1 cos2x 1 sin2x = sin2x cos2x sin2x ⋅ cos2x = 1 cos2x ⋅ csc2x = sec2x ⋅ csc2x = RH S Answer linkUse the identities sec^2 (x) = tan^2 (x) 1 and csc^2 (x) = 1 cot^2 (x), both are derived from the pythagorean identity of 1 = sin^2 (x) cos^2 (x) by dividing through by either sin 2 or cos 2 2 View Entire Discussion (1 Comments)
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(sec^2x+tan^2x)(cosec^2x+cot^2x)=1+2 sec^2x cosec^2x
(sec^2x+tan^2x)(cosec^2x+cot^2x)=1+2 sec^2x cosec^2x-
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